What would be the pH of a solution prepared by combining equal quantities of NaH2PO4 and Na2HPO4? Explain with an equation.

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  1. It will be pKa2.
    pH = pKa2 + log[(base)/(acid)]
    If base = acid, then log 1 = 0 and pH = pKa2.

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  2. How do u find pKa2

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  3. Look up Ka2, (and Ka1 and Ka3 will be in the same table) for H3PO4.
    Then pKa2 = -log(Ka2) = ?

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  4. ka2=6.2x10^-8

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