How to prepare 1L of 96% v/v ethanol from 99% v/v ethanol? Can you show me the calculation steps?Thanks.

I think you can use the dilution formula of c1v1 = c2v2

To prepare 1L of 96% v/v ethanol from 99% v/v ethanol, you need to calculate the amount of 99% v/v ethanol and the amount of water required. Here are the steps:

Step 1: Determine the final volume:
Since you want to prepare 1L of final solution, the final volume is 1L.

Step 2: Write down the initial volume and percentage of ethanol:
The initial volume is unknown, and the percentage is 99% v/v.

Step 3: Write down the final volume and desired percentage of ethanol:
The final volume is 1L, and the desired percentage is 96% v/v.

Step 4: Calculate the required volume of 99% v/v ethanol:
Let's call this volume "V1".

V1 x 0.99 = 1L x 0.96

V1 = (1L x 0.96) / 0.99

Step 5: Calculate the volume of water needed:
The volume of water needed is equal to the final volume minus the volume of 99% v/v ethanol.

Water volume = 1L - V1

Step 6: Convert the volumes to mL (if desired):
If you prefer to work with mL instead of L, you can convert the volumes accordingly. Multiply the volumes by 1000 since there are 1000mL in 1L.

Note: The values obtained from the calculations might not be whole numbers, so rounding them would be necessary.

Following these steps, you can calculate the specific values for V1 and the volume of water needed to prepare 1L of 96% v/v ethanol from 99% v/v ethanol.

To prepare 1L of 96% v/v ethanol from 99% v/v ethanol, you can use the formula:

(V1 x C1) = (V2 x C2)

Where:
V1 = Volume of the concentrated solution (99% v/v ethanol)
C1 = Concentration of the concentrated solution (99% v/v ethanol)
V2 = Desired volume of the diluted solution (1L)
C2 = Desired concentration of the diluted solution (96% v/v ethanol)

Let's calculate the volume of the concentrated solution (V1) that needs to be taken and then dilute it to achieve the desired concentration:

(V1 x 99%) = (1L x 96%)

Divide both sides by 99%:

V1 = (1L x 96%) / 99%
V1 = 0.9697L

So, to prepare 1L of 96% v/v ethanol from 99% v/v ethanol, you need to take approximately 0.9697L of the 99% v/v ethanol and then dilute it with diluent (e.g., water) to achieve a final volume of 1L.

Please note that in practice, it's recommended to measure the volume accurately using a graduated cylinder or pipette for precise dilutions.