The rider sees a traffic queue ahead. He applies the brakes and reduces the speed of the

motorbike from 18 m/s to 3 m/s.
Use the equation in the box to calculate the kinetic energy lost by the motorbike.

1 over 2× mass × speed

Hmmm.

energy lost= original energy-finalenergy
= 1/2 m (18^2-3^2)

To calculate the kinetic energy lost by the motorbike, we need to use the equation:

Kinetic Energy = 1/2 × mass × speed^2

In this case, the mass of the motorbike is not given, but we know the initial speed (18 m/s) and the final speed (3 m/s). We will assume a mass value to proceed with the calculation.

Let's say we assume the mass of the motorbike to be 200 kg. Now we can substitute the values into the equation and calculate the kinetic energy lost:

Initial Speed = 18 m/s
Final Speed = 3 m/s
Mass = 200 kg (assumed value)

Kinetic Energy = 1/2 × 200 kg × (3 m/s)^2

First, let's square the final speed:

(3 m/s)^2 = 3 m/s × 3 m/s = 9 m^2/s^2

Now, substitute the values:

Kinetic Energy = 1/2 × 200 kg × 9 m^2/s^2

To simplify the calculation, let's calculate the value inside the bracket first:

1/2 × 200 kg × 9 m^2/s^2 = 900 J

Therefore, the kinetic energy lost by the motorbike is 900 Joules (J).

Note: The assumed mass value is just for calculation purposes. To get the precise value, the actual mass of the motorbike should be provided.