Question

Find dy/dx if x^2+y^2= /5

*(/5= square root of 5)*

Answer 1

any constant 1 , 0 , 2 , pi , square root its derivative = 0

so
dy/dx x^2+y^2= sqrt(5)

2 x x' + 2 y y' = 0 [x' = 1]

2x + 2yy'=0 ] /2

x + yy' = 0

y' = - x/y