On standard IQ tests, the mean is 110 and the standard deviation is 15. The results are very close to fitting a normal curve. Suppose an IQ test is given to a very large group of people. Find the percent of people whose IQ score is less than 155.

Use the same process as indicated in my response to your previous post.

Suppose you are given data from a survey showing the IQ of each person interviewed and the IQ of his or her mother. That is all the information you have. Your boss has asked you to put together a report showing the relationship between these two variables. What could you present and why?

To find the percent of people whose IQ score is less than 155, we can use the Z-score formula and the standard normal distribution table.

First, we calculate the Z-score using the formula:

Z = (X - mean) / standard deviation

In this case, X represents 155, the IQ score we want to find the percentage for. The mean is given as 110, and the standard deviation is given as 15.

Z = (155 - 110) / 15
Z = 45 / 15
Z = 3

Next, we need to use the standard normal distribution table. This table provides the cumulative area under the standard normal curve up to a certain Z-score.

Looking up the Z-score of 3 in the standard normal distribution table, we find that the cumulative area is approximately 0.9987.

This means that approximately 99.87% of people have an IQ score less than 155.

Therefore, the percent of people whose IQ score is less than 155 is 99.87%.