What will be the concentration if 52mL of a solution that is 12ppm in sodium chloride is diluted with enough water to make 97mL of solution?
12 ppm x (52mL/97 mL) = ?ppm
To find the concentration of the diluted solution, we can use the formula:
C1V1 = C2V2,
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
In this scenario, we are given:
C1 = 12 ppm,
V1 = 52 mL,
V2 = 97 mL.
We want to find C2, the final concentration.
Rearranging the formula, we have:
C2 = (C1 * V1) / V2.
Substituting the given values:
C2 = (12 ppm * 52 mL) / 97 mL.
Now, let's calculate:
C2 = (624 ppm * mL) / 97 mL.
Dividing the units of milliliters (mL), we find:
C2 = 6,432 ppm / 97.
Simplifying the expression:
C2 ≈ 66.49 ppm.
Therefore, the concentration of the diluted solution is approximately 66.49 ppm.