Consider the following reaction.
2KClO3(s) �¨ 2KCl(s) + 3O2(g)
A)How many grams of KCl are produced from the complete reaction of 10.9 mol of KClO3?
B)How many grams of KCl are produced from the complete reaction of 86.2 g of KClO3?
The balanced reaction indicates you will get 10.9moles of potassium chloride (mole ratio 2:2). So how many grams of KCl is that?
massKCl=moleKCl*formula mass KCl
b. figure first the moles of potassium chlorate in 86.2 g (
molesKClO3=mass/formalaMass KClO3
then, proceed as in a
13.27
To solve both parts A and B of the question, we need to use stoichiometry. Stoichiometry allows us to relate the quantities of reactants and products in a chemical reaction.
First, let's analyze the balanced equation:
2KClO3(s) → 2KCl(s) + 3O2(g)
The coefficients in front of each compound represent the mole ratio between the reactants and products. According to the balanced equation, for every 2 moles of KClO3, we get 2 moles of KCl.
A) To find the number of grams of KCl produced from the complete reaction of 10.9 mol of KClO3, we can use the molar mass of KCl to convert from moles to grams.
Step 1: Calculate the molar mass of KCl.
Molar mass of KCl = atomic mass of K + atomic mass of Cl = 39.10 g/mol + 35.45 g/mol = 74.55 g/mol
Step 2: Use the stoichiometry to find the number of moles of KCl produced.
Since the mole ratio between KClO3 and KCl is 2:2, this means that for every 2 moles of KClO3, we get 2 moles of KCl.
Number of moles of KCl = 10.9 mol * (2 mol KCl/2 mol KClO3) = 10.9 mol
Step 3: Convert moles to grams using the molar mass of KCl.
Mass of KCl = Number of moles of KCl * Molar mass of KCl = 10.9 mol * 74.55 g/mol = 811 g
Therefore, from the complete reaction of 10.9 mol of KClO3, 811 grams of KCl are produced.
B) To find the number of grams of KCl produced from the complete reaction of 86.2 g of KClO3, we can use the molar mass of KClO3 to convert from grams to moles. Then, we can use stoichiometry to find the number of grams of KCl.
Step 1: Calculate the molar mass of KClO3.
Molar mass of KClO3 = atomic mass of K + atomic mass of Cl + 3*(atomic mass of O) = 39.10 g/mol + 35.45 g/mol + 3*(16.00 g/mol) = 122.55 g/mol
Step 2: Convert grams of KClO3 to moles using the molar mass of KClO3.
Number of moles of KClO3 = Mass of KClO3 / Molar mass of KClO3 = 86.2 g / 122.55 g/mol = 0.703 mol
Step 3: Use stoichiometry to find the number of moles of KCl produced.
Since the mole ratio between KClO3 and KCl is 2:2, this means that for every 2 moles of KClO3, we get 2 moles of KCl.
Number of moles of KCl = 0.703 mol * (2 mol KCl/2 mol KClO3) = 0.703 mol
Step 4: Convert moles to grams using the molar mass of KCl.
Mass of KCl = Number of moles of KCl * Molar mass of KCl = 0.703 mol * 74.55 g/mol = 52.3 g
Therefore, from the complete reaction of 86.2 g of KClO3, 52.3 grams of KCl are produced.