A 300 mL sample of hydrogen gas is at a pressure of 0.500 kPa. If the pressure increases to 0.750 kPa, what will be the final volume of the sample? Assume that the temperature stays constant
I think this is a duplicate post.
yes it is sorry i did not mean to post this twice
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when temperature remains constant. The formula for Boyle's Law is:
P1 * V1 = P2 * V2
where P1 and P2 are the initial and final pressures, and V1 and V2 are the initial and final volumes, respectively.
Given:
P1 = 0.500 kPa
V1 = 300 mL
P2 = 0.750 kPa
V2 = ?
Let's substitute the values into the formula and solve for V2:
(0.500 kPa) * (300 mL) = (0.750 kPa) * (V2)
Simplifying the equation:
150 kPa * mL = 0.750 kPa * V2
Dividing both sides by 0.750 kPa:
200 mL = V2
Therefore, the final volume of the sample will be 200 mL when the pressure increases to 0.750 kPa.
To find the final volume of the sample, we can use the combined gas law equation, which relates the initial and final pressure and volume of a gas sample:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 and P2 are the initial and final pressures, respectively.
V1 and V2 are the initial and final volumes, respectively.
T1 and T2 are the initial and final temperatures, respectively.
In this case, we are given:
P1 = 0.500 kPa
V1 = 300 mL
P2 = 0.750 kPa
T1 and T2 are assumed to be constant.
Since the temperature does not change, we can simplify the equation to:
P1 * V1 = P2 * V2
Now, we can plug in the given values to solve for V2:
(0.500 kPa * 300 mL) = (0.750 kPa * V2)
To solve for V2, we can rearrange the equation:
V2 = (0.500 kPa * 300 mL) / 0.750 kPa
V2 = 200 mL
Therefore, the final volume of the hydrogen gas sample will be 200 mL.