A jet leaves the airport traveling at an average rate of 564km/h. Another jet leaves the same airport traveling at a rate of 744km/h in the same direction. How long will it take for the second jet to reach the first jet
Did they leave at the same time?
They could not have left at the same time. Jacob-you left part of the problem out.
When you get it figured out, the distances are the same
d = rate * time
rate jet1 * time jet 1 = rate jet2 *(time jet 1 - delay)
no the second one left a half an hour later sorry i forgot to include that
then
564 *t = 744 * (t - .5)
solve for t, the time for jet 1
then if we want the time for jet 2, subtract 1/2 hour
564t=744(t-.5)
564t=744t-372
564t-564t=744t-372-564t
0=180t-372
0+372=180t-372+372
372=180t
372/180=180t/180
2.07=t
Is that correct?
Yes
But remember to subtract half hour for second plane
ok thank you for all of your help
564*2.07=744*2.07-.5
564*2.07=744*1.57
1167.48=1168.08
how come it doesnt equal the same thing?
To find out how long it will take for the second jet to reach the first jet, we need to know the distance between them. However, the question does not provide this information.
If we assume that the jets start at the same time, we can set up an equation based on their speeds and the time it takes for the second jet to catch up to the first.
Let's call the time it takes for the second jet to catch up to the first "t" (in hours).
Since the distance both jets travel (d) will be the same when the second jet catches up to the first, we can set up the following equation:
Distance traveled by the first jet = Distance traveled by the second jet
564t = 744t
Now, we can solve for "t" by dividing both sides of the equation by 564:
t = 744 / 564
t ≈ 1.32 hours
Therefore, it will take approximately 1.32 hours for the second jet to reach the first jet.