How long does it take a 19 kW steam engine to do 6.8x10^7 of work?
I have no idea how to solve this... Would someone please help?
You omitted the dimensions of the work in your quetion. We assume it is in Joules
I'm pretty sure Damon meant 6.8 instead of 6.9 in his number for the work done. With that change, both previous answers agree.
t = 3579 s
With only 2 significant figures in the input numbers, the answer should be stated as 3600 s or one hour.
To determine how long it takes for a 19 kW steam engine to do 6.8x10^7 joules (J) of work, we can use the formula:
work = power x time
In this case, the power is given as 19 kilowatts (kW), which we need to convert to joules per second (J/s) since work is measured in joules and time will be in seconds.
1 kilowatt (kW) = 1000 joules per second (J/s)
So, we can convert 19 kW to J/s by multiplying by 1000:
19 kW x 1000 J/s per kW = 19000 J/s
Now, we can rearrange the formula to solve for time:
time = work / power
Plugging in the values:
time = 6.8x10^7 J / 19000 J/s
To divide by a fraction, we can multiply by its reciprocal:
time = 6.8x10^7 J * (1/19000 s/J)
Multiplying the numbers:
time = 3589.47 seconds
Therefore, it would take approximately 3589.47 seconds for the 19 kW steam engine to do 6.8x10^7 J of work.
well 1 W = J/s So, 19 kW is 19000 J/s. But you want to find time, so you want to have seconds in the denominator, you you would multiply the inverse of the watts times the amount of work.
so (1 sec/19000 J) * (6.8 X 10^7 J)
Joules should cancel out with joules and you should be left with seconds.
power = 19*10^3 Watts = 19*10^3 Joules/s
work = power * time
6.9*10^7 J = 19 * 10^3 J/s * t
so
t = 6.9*10^7 / 19*10^3