can anyone please help me solve this step by step by using the quadratic formula..

-4t^2-9t-3=0

see below

t = -b/2a +/- (1/2a) sqrt (b^2 - 4 a c)

a = 4
b = 9 Note = I multiplied both side by -1
c = 3

t = -9/8 +/- (1/8) sqrt(81 - 48)

t = -9/8 +/- (1/8)sqrt (33)

t = [ -9+sqrt(33) ]/8
or
t = [ -9-sqrt(33) ]/8

DanH

I think you have a sign mistake
-b/2a = -(-9)/(-8) = -9/8

Certainly! To solve the quadratic equation "-4t^2 - 9t - 3 = 0" using the quadratic formula, follow these steps:

Step 1: Identify the coefficients of the quadratic equation. In this case, the coefficients are:
a = -4
b = -9
c = -3

Step 2: Substitute the coefficients into the quadratic formula:
The quadratic formula is t = (-b ± √(b^2 - 4ac)) / 2a

Substituting the values, we get:
t = (-(-9) ± √((-9)^2 - 4(-4)(-3))) / 2(-4)

Simplifying further:
t = (9 ± √(81 - 48)) / -8
t = (9 ± √33) / -8

Step 3: Evaluate both possible solutions:
To find the two possible values of t, calculate:
t1 = (9 + √33) / -8
t2 = (9 - √33) / -8

These are the two solutions to the quadratic equation: t1 and t2.

So, the step-by-step solution to "-4t^2 - 9t - 3 = 0" using the quadratic formula is:
t1 = (9 + √33) / -8
t2 = (9 - √33) / -8