Sean is playing a game where you toss a coin and roll a number cube. How many possible outcomes?Show it as a fraction,decimal, and a percent. If p= probability, what is P( heads,odd)??? Please answer very urgent!!!!
1/6 probability that it will land on a number each time.
P(heads,odd) = 1/2 * 3/6 = 1/4
To determine the number of possible outcomes in the game, we need to consider the outcomes of tossing a coin and rolling a number cube separately.
Tossing a coin has 2 possible outcomes: heads (H) or tails (T). Rolling a number cube has 6 possible outcomes: 1, 2, 3, 4, 5, or 6.
To find the total number of possible outcomes in the game, we multiply the number of outcomes for each event. In this case, it will be 2 (coin outcomes) multiplied by 6 (number cube outcomes), which gives us 12 possible outcomes.
Now let's represent this as a fraction, decimal, and percent:
Fraction: Since there are 12 possible outcomes, we write it as 12/1.
Decimal: To express it as a decimal, we divide the number of successful outcomes by the total number of possible outcomes. In this case, there is only one possible outcome of getting heads and an odd number (H1 or H3 or H5), so the decimal representation would be 1/12 ≈ 0.0833 (rounded to four decimal places).
Percent: To convert the decimal to a percentage, we multiply it by 100. So 0.0833 multiplied by 100 is approximately 8.33%.
Therefore, P(heads, odd) = 1/12 ≈ 0.0833 ≈ 8.33%.