An 800-kg car traveling in a straight line at a speed of 30 m/s applies its brakes. During braking, there is a net force of 2000 N in the horizontal direction on the car. What distance will the car move from the time it applies its brakes until it has stopped?

a = Fn/m = 2000 / 800 =- 2.5 m/s^2.

d = (Vf^2-Vo^2)/2a,
d = (0-(30)^2 / -5 = 180 m.

To find the distance the car will move from the time it applies its brakes until it has stopped, we can use the concept of kinematics.

Step 1: Determine the acceleration of the car.
We know that the net force acting on the car is 2000 N. To find the acceleration, we use Newton's second law, which states that force equals mass multiplied by acceleration (F = m * a).

Rearranging the equation, we have:
a = F / m
a = 2000 N / 800 kg
a = 2.5 m/s²

Step 2: Find the time it takes for the car to stop.
To find the time it takes for the car to stop, we need to use the equation of motion:

v = u + at

Where:
v = final velocity (0 m/s, as the car has stopped)
u = initial velocity (30 m/s)
a = acceleration (-2.5 m/s², negative because it opposes the car's initial motion)
t = time

Rearranging the equation, we have:
0 = 30 m/s + (-2.5 m/s²) * t

Simplifying further, we get:
2.5 t = 30
t = 30 / 2.5
t = 12 s

Step 3: Calculate the distance traveled.
To find the distance traveled, we can use the equation:

s = ut + (1/2)at²

Where:
s = distance
u = initial velocity (30 m/s)
t = time (12 s)
a = acceleration (-2.5 m/s²)

Plugging in the values, we have:
s = 30 m/s * 12 s + (1/2) * (-2.5 m/s²) * (12 s)²

Simplifying further, we get:
s = 360 m + (-180 m)
s = 180 m

Therefore, the car will move a distance of 180 meters from the time it applies its brakes until it has stopped.