You are holding a bulletin board weighing 6.46 N in place against a wall while your friend secures it to the wall. To keep it from slipping, you apply a force perpendicular to the bulletin board, pressing it directly into the wall. How large must this force be if the coefficient of static friction with the wall is 0.43?

To determine the force required to keep the bulletin board from slipping, we need to consider the influence of friction. The force required is equal to the maximum static friction force that can be exerted between the bulletin board and the wall.

The maximum static friction force can be calculated using the formula:

Maximum Static Friction Force (Fmax) = Coefficient of Static Friction (μ) × Normal Force (N)

In this case, the normal force acting on the bulletin board is equal to its weight. The weight is given as 6.46 N, so the normal force is also 6.46 N.

Now we can calculate the force required to keep the bulletin board from slipping:

Fmax = 0.43 × 6.46 N

Fmax = 2.7818 N

Therefore, the force required to keep the bulletin board from slipping is approximately 2.7818 Newtons.