A bag contains a mixture of copper and lead BBs. The average density of the BBs is 9.60g/cm cubed. What is the percent of copper and the percent of lead?
To find the percent of copper and lead, we need more information such as the individual densities of copper and lead. The average density alone is not sufficient to determine the percentages of each component.
To find the percent of copper and lead in the mixture, you need to know the densities of copper and lead BBs, as well as their respective percentages in the mixture.
Let's assume the density of copper is denoted as dc and the density of lead as dl. Also, let's assume the percent of copper in the mixture is denoted as pc, and the percent of lead as pl.
The average density of the BBs is given as 9.60 g/cm³. We can use this information to create an equation:
Average density = (pc * dc) + (pl * dl)
Substituting the values and variables we have:
9.60 g/cm³ = (pc * dc) + (pl * dl) ---(Equation 1)
Next, we need to consider that the percentages of copper and lead should add up to 100%, so we have:
pc + pl = 100
To solve this system of equations, we need the values of dc and dl, which represent the densities of copper and lead respectfully. These values can be found in a reference book or online source.
Once you have the values of dc and dl, you can substitute them into Equation 1, along with the known average density of 9.60 g/cm³, to solve for pc and pl.