At an instant when a soccer ball is in contact with the foot of a player kicking it, the horizontal or x component of the ball's acceleration is 810m/s^2 and the vertical or y component of its acceleration is 110m/s^2. The ball's mass is 0.43kg. what is the magnitude of the net force acting on the soccer boll at this instant?

X = 810 m/s^2.

Y = 110 m/s^2.

a = sqrt(X^2 + Y^2),
a = sqrt(656100+12100) = 814 m/s^2.

Fn = ma = 0.43 * 814 = 350 N.=Net force.

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 790 m/s2 and the vertical or y component of its acceleration is 900 m/s2. The ball's mass is 0.36 kg. What is the magnitude of the net force acting on the soccer ball at this instant?

Well, if we want to find the magnitude of the net force acting on the soccer ball, we need to use Newton's second law of motion, which states that force equals mass times acceleration. Since we know the mass of the ball is 0.43kg, and we have both the horizontal and vertical components of its acceleration, we can calculate the magnitude of the net force.

Let's start with the horizontal component of the acceleration: 810 m/s^2. We can use this information to calculate the horizontal component of the net force.

F_net_x = m * a_x = 0.43 kg * 810 m/s^2 = 349.3 N

Now, let's move on to the vertical component of the acceleration: 110 m/s^2. We can use this information to calculate the vertical component of the net force.

F_net_y = m * a_y = 0.43 kg * 110 m/s^2 = 47.3 N

To find the magnitude of the net force, we can use the Pythagorean theorem.

Magnitude of the net force = sqrt(F_net_x^2 + F_net_y^2) = sqrt(349.3^2 + 47.3^2) = sqrt(121799.49 + 2239.29) = sqrt(124038.78) ≈ 352.24 N

So, the magnitude of the net force acting on the soccer ball at this instant is approximately 352.24 N.

To find the magnitude of the net force acting on the soccer ball at this instant, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.

Given:
Horizontal (x) component of acceleration (ax) = 810 m/s^2
Vertical (y) component of acceleration (ay) = 110 m/s^2
Mass of the ball (m) = 0.43 kg

First, we need to find the magnitude of the total acceleration (a) of the soccer ball at this instant. The magnitude of acceleration can be calculated using the Pythagorean theorem:

a = √(ax^2 + ay^2)

Substituting the given values:

a = √(810^2 + 110^2) = √(656100 + 12100) = √668200 ≈ 817.16 m/s^2

Now that we know the magnitude of acceleration, we can calculate the net force (F) using Newton's second law:

F = m * a

Substituting the given values:

F = 0.43 kg * 817.16 m/s^2 ≈ 351.6728 N

Therefore, the magnitude of the net force acting on the soccer ball at this instant is approximately 351.67 N.

Armadillos are incredibly good jumpers and can jump 92 cm to 122 cm (about 3-4 feet) into the air and tend to jump when scared. A Paulo the armadillo jumps with a speed of 4.7 m/s. How long is Paulo in the air.