In the reaction of N2 and H2 to produce NH3, how many moles of N2 will produce 25.9 moles NH3?
N2 + 3H2 ==?> 2NH3
So you want 25.9 moles NH3.
Convert 25.9 moles NH3 to moles N2.
25.9 mol NH3 x (1 mol N2/2 moles NH3) = 25.9 x 1/2 = ?
Well, if you want some mole-y funny business, here's the deal. In the reaction of N2 and H2 to produce NH3, the balanced equation is:
N2 + 3H2 -> 2NH3
So for every 1 mole of N2, you get 2 moles of NH3. In other words, it's a 1:2 ratio.
But here's where it gets interesting (or maybe not), if you have 25.9 moles of NH3 that you want to produce, you'll need half of that amount in moles of N2. So, 25.9 divided by 2 is...
*drumroll, please*
12.95 moles of N2!
And if that answer doesn't leave you feeling gas-terly amused, I don't know what will!
To determine how many moles of N2 are needed to produce 25.9 moles of NH3, we need to use the balanced equation for the reaction. The balanced equation for the reaction of N2 and H2 to produce NH3 is:
N2 + 3H2 -> 2NH3
From the balanced equation, we can see that 1 mole of N2 reacts to produce 2 moles of NH3. Therefore, we can set up a proportion to calculate the number of moles of N2 needed:
(1 mole N2 / 2 moles NH3) = (x moles N2 / 25.9 moles NH3)
Cross-multiplying and solving for x, we get:
x = (1 mole N2 / 2 moles NH3) * 25.9 moles NH3
x = 12.95 moles N2
Therefore, approximately 12.95 moles of N2 are needed to produce 25.9 moles of NH3.
To determine the number of moles of N2 required to produce 25.9 moles of NH3, we need to look at the balanced chemical equation for the reaction of N2 and H2 to produce NH3.
The balanced equation for this reaction is:
N2 + 3H2 -> 2NH3
From the balanced equation, we can see that for every 1 mole of N2, we produce 2 moles of NH3.
So, we can set up a ratio using the coefficients in the balanced equation:
1 mole N2 / 2 moles NH3
Now, we can use this ratio to find the number of moles of N2:
Moles of N2 = Moles of NH3 * (1 mole N2 / 2 moles NH3)
Plugging in the values, we get:
Moles of N2 = 25.9 moles NH3 * (1 mole N2 / 2 moles NH3)
Simplifying the expression:
Moles of N2 = 25.9 moles NH3 / 2
Moles of N2 = 12.95 moles
Therefore, 12.95 moles of N2 are required to produce 25.9 moles of NH3.