A circuit consists of a 12.0 V battery connected to three resistors 44 ohms, 15 ohms and 120 ohms in series.
A)Find the current that flows through the battery.
B)Find the potential difference across the 44 Ohms resistor.
C)Find the potential difference across the 15 ohms resistor.
D)Find the potential difference across the 120 Ohms resistor.
a. find Rtotal= sum resistors
I=12/rtotal
b. V44=I*44
To solve this problem, we can apply Ohm's Law and the rules for series circuits.
A) To find the current that flows through the battery, we can use Ohm's Law, which states that current (I) is equal to the voltage (V) divided by the resistance (R). In this case, the voltage is 12.0 V and the total resistance (R_total) of the circuit is the sum of the individual resistances (R1, R2, R3).
R_total = R1 + R2 + R3 = 44 ohms + 15 ohms + 120 ohms = 179 ohms
Using Ohm's Law, we can calculate the current (I):
I = V / R_total = 12.0 V / 179 ohms
B) To find the potential difference across the 44 ohms resistor, we can use Ohm's Law again. Since the potential difference across a resistor in a series circuit is the same as the battery voltage, the potential difference across the 44 ohms resistor is equal to the battery voltage, which is 12.0 V.
C) Similarly, the potential difference across the 15 ohms resistor is also equal to the battery voltage, which is 12.0 V.
D) Finally, the potential difference across the 120 ohms resistor can be calculated by using Ohm's Law:
V = I * R = (12.0 V) * (120 ohms) / 179 ohms
Now, you can calculate the potential difference across the 120 ohms resistor using the given formula.
To solve this circuit problem, you need to apply Ohm's law, which states that the current flowing through a conductor is directly proportional to the voltage across it and inversely proportional to its resistance. Ohm's law can be expressed using the formula V = IR, where V is the potential difference (voltage) across the conductor, I is the current flowing through the conductor, and R is the resistance of the conductor.
Now let's solve the given circuit problem step by step:
A) To find the current that flows through the battery, you need to apply Ohm's law to the total resistance of the circuit. In a series circuit, the total resistance is equal to the sum of the individual resistances. So, the total resistance (R) in this circuit is 44 + 15 + 120 = 179 ohms.
Now, you can use Ohm's law again, this time using the potential difference (V) as the battery voltage (12.0 V) and the total resistance (R) as 179 ohms. Rearranging the formula V = IR, you can solve for I (the current): I = V/R.
I = 12.0 V / 179 ohms
I ≈ 0.067 A (rounded to three decimal places)
Therefore, the current that flows through the battery is approximately 0.067 Amperes.
B) To find the potential difference (V) across the 44-ohm resistor, you can use Ohm's law again, this time using the known current (I) and resistance (R). Rearranging the formula V = IR, you can solve for V:
V = I * R
V = 0.067 A * 44 ohms
V ≈ 2.95 V (rounded to two decimal places)
Therefore, the potential difference across the 44 ohms resistor is approximately 2.95 Volts.
C) To find the potential difference (V) across the 15-ohm resistor, you can use Ohm's law again, using the known current (I) and resistance (R). Rearranging the formula V = IR, you can solve for V:
V = I * R
V = 0.067 A * 15 ohms
V ≈ 1.01 V (rounded to two decimal places)
Therefore, the potential difference across the 15 ohms resistor is approximately 1.01 Volts.
D) To find the potential difference (V) across the 120-ohm resistor, you can use Ohm's law again, using the known current (I) and resistance (R). Rearranging the formula V = IR, you can solve for V:
V = I * R
V = 0.067 A * 120 ohms
V ≈ 8.04 V (rounded to two decimal places)
Therefore, the potential difference across the 120 ohms resistor is approximately 8.04 Volts.