an electronics store receives a shipment of 40 graphing calculators including 3 that are defective. Four of the calculators are sleceted to be sent to a local high school. How many selections can be made using the original shipment

To find out how many selections can be made from the original shipment of 40 graphing calculators, we will use the concept of combinations.

The number of selections can be calculated using the formula for combinations:

C(n, r) = n! / (r!(n-r)!)

Where:
n is the total number of items (in this case, the total number of graphing calculators in the shipment)
r is the number of items selected (in this case, the number of calculators to be sent to the high school)

In this case, n = 40 (total number of graphing calculators) and r = 4 (number of calculators to be sent to the high school).

Using the formula, we can calculate the number of selections:

C(40, 4) = 40! / (4!(40-4)!)
= 40! / (4! * 36!)
= (40 * 39 * 38 * 37 * 36!) / (4! * 36!)
= (40 * 39 * 38 * 37) / (4 * 3 * 2 * 1)
= 91,390

Therefore, there are 91,390 different selections that can be made from the original shipment of 40 graphing calculators.

MathMate answered the same question last March, except there were 20 calculators instead of your 40

make the corresponding changes.

http://www.jiskha.com/display.cgi?id=1299561374