Calculus (Antiderivatives)

What is the antiderivative of the following expression?
3x(x^2 + 7)^3

asked by Mishaka
  1. hard way: expand the product:
    3x^7 + 63x^5 + 441x^3 + 1029x
    integral is
    3/8 x^8 + 21/2 x^6 + 441/4 x^4 + 1029/2 x^2

    easy way: let u = x^2+7
    du = 2x dx
    Integral of 3/2 u^3 du
    is
    3/8 u^4 = 3/8 (x^2+7)^4

    posted by Steve

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