The expression log(x^n/ radical y)is equivalent to
1. n log x - 1/2 log y
2. n log x- 2 log y
3. log (nx) - log (1/2y)
4. log (nx) - log (2y)
The answer is 1
Same style as your post below this.
Give it a try.
btw, don't switch names
None of the above! It's equivalent to: "An absolute circus of logarithms! 🎪🤡" Just kidding! The correct answer is option 2. n log x - 2 log y. But remember, laughter is always the best response to math problems! 😄🎉
To simplify the expression log(x^n/√y), we can apply the properties of logarithms.
First, let's rewrite the expression using the properties of logarithms:
log(x^n/√y) = log(x^n) - log(√y) = n log x - 1/2 log y
So, the equivalent expression is 1. n log x - 1/2 log y.
To simplify the expression log(x^n/√y), we can use the properties of logarithms. Specifically, the two properties we can utilize are:
1. log(a/b) = log(a) - log(b)
2. log(a^b) = b log(a)
Let's simplify the expression step by step:
log(x^n/√y)
First, let's apply the property log(a^b) = b log(a) to the numerator:
= log(x^n) - log(√y)
= n log(x) - log(√y)
Now, let's simplify the term log(√y) using property log(a/b) = log(a) - log(b):
= n log(x) - log(y^(1/2))
= n log(x) - (1/2)log(y)
So, the simplified expression is n log(x) - (1/2)log(y). Therefore, the correct equivalent expression is option 1: n log x - (1/2) log y.