when 7.50 grams of iodine (I2) is added to 48.7grams of carbon tetrachloride (CCl4), the iodine dissolves and a solution is formed. The weight percent of the iodine in the solution is?
7.50g I2/ 7.50 + 48.7 X 100 = 13.3
Did I do this correctly?
Yes, but to avoid your calculation being misinterpreted I would show it this way.
(7.50/7.50+48.7) x 100 = 13.3%
Yes, you calculated the weight percent correctly. The weight percent of iodine in the solution can be calculated using the formula:
Weight percent = (mass of iodine / total mass of solution) × 100
In this case, the mass of iodine is given as 7.50 grams and the total mass of the solution is the sum of the mass of iodine (7.50 grams) and the mass of carbon tetrachloride (48.7 grams). Plugging these values into the formula:
Weight percent = (7.50 grams / (7.50 grams + 48.7 grams)) × 100
= (7.50 grams / 56.20 grams) × 100
≈ 13.32 %
Therefore, the weight percent of iodine in the solution is approximately 13.32%.