Find the volume of the solid generated by revolving the region bounded by y= 5 cosh (x) and y= 5 sinh (x) between x = 0 and x = 1 about the x-axis
v = Int(pi*(R^2-r^2) dx) [0,1]
where
R = 5cosh(x)
r = 5sinh(x)
v = 5pi*Int(cosh(x) - sinh(x) dx) [0,1]
= 5pi*(sinh(x)-cosh(x))[0,1]
=5pi*[(sinh(1)-cosh(1))-(sinh(0)-cosh(0))
= 5pi*(-1/e + 1)
= 5pi(e-1)/e