physics

An electron (mass m = 9.11 * 10^-31 kg) is accelerated in a uniform field vector E ( E =1.45 * 10^4 N/C) between two parallel charged plates. The seperation of the plates is 1.10 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate.
a) With what speed does it leave the hole?
b) Show that the gravitational force can be ignored.

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asked by jenish
  1. a) e E d = (1/2) mV^2
    d is the plate separation
    e amd m are the electron charge and mass, respiectively.
    Solve for V
    b) Compare Ee, (the electric force) to mg (the gravity force). The ratio may surprise you.

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    posted by drwls
  2. 0879798

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    posted by Anonymous

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