The density of ice is 0.92 g cm-3 & that of sea water is 1.025 g cm-3.Find total volume of an iceberg which floats with its volume 800 cm3 above water.
ANSWER:7809.5 cm3
To find the total volume of the iceberg, we need to consider its submerged volume and the portion that is above the water.
Let's assume the submerged volume of the iceberg is V_iceberg_submerged and the volume above water is 800 cm³.
We can use the density of ice and sea water to calculate the submerged volume.
Density of ice = 0.92 g/cm³
Density of sea water = 1.025 g/cm³
Since the iceberg is floating, the submerged volume of the iceberg displaces an equal volume of sea water. Therefore, the weight of the submerged portion of the iceberg is equal to the weight of the volume of sea water it displaces.
The weight of the submerged portion can be calculated using the following formula:
Weight_submerged = Density_sea water * V_iceberg_submerged
On the other hand, the weight of the volume of sea water displaced is given by:
Weight_displaced = Density_sea water * V_iceberg_submerged
Since the weight of the submerged portion is equal to the weight of the displaced volume, we can equate these two expressions:
Density_sea water * V_iceberg_submerged = Density_ice * 800 cm³
Rearranging the equation, we find:
V_iceberg_submerged = (Density_ice / Density_sea water) * 800 cm³
V_iceberg_submerged = (0.92 / 1.025) * 800 cm³
V_iceberg_submerged ≈ 709.8 cm³
The total volume of the iceberg can be calculated by adding the submerged volume and the volume above water:
Total volume = V_iceberg_submerged + 800 cm³
Total volume ≈ 709.8 cm³ + 800 cm³
Total volume ≈ 1509.8 cm³
Therefore, the total volume of the iceberg is approximately 1509.8 cm³.
the ice is floating,so net force is zero.
to get that net force, then
net force= weight of water displaced-weight of iceberg
net force= 1.025( Vunder)-.92(800+Vunder)
solve for Vunder.
Vunder=.92*800/(1.025-.92)
check that math