math. can someone explain this!

using this information: if an object is thrown straight up into the air from the height H feet per second then at time tseconds the height of the object is
-16.1t^2 +Vt+ H feet.
This formula uses only gravitational force, ignoring air friction. It is valid only until the object hits the ground or some other object.

Find a function b such that b(v) is the length of time in seconds that a ball takes to reach its maximum height when thrown straight up with initial velocity V feet per second

asked by deana

Respond to this Question

First Name

Your Response

Similar Questions

  1. math

    using this information: if an object is thrown straight up into the air from the height H feet per second then at time tseconds the height of the object is -16.1t^2 +Vt+ H feet. This formula uses only gravitational force, ignoring
  2. math

    using this information: if an object is thrown straight up into the air from the height H feet per second then at time tseconds the height of the object is -16.1t^2 +Vt+ H feet. This formula uses only gravitational force, ignoring
  3. math

    An object that is falling or vertically projected into the air has it height, in feet, above the ground given by the formula below, where s is the height in feet, Vo is the original velocity of the object, in feet per second, t is
  4. calculus 2

    An object thrown in the air on a planet in a distant galaxy is at height s(t) = -20t^2 +67t +42 feet at time t seconds after it is thrown. a) From what height was the object thrown? b) With what velocity was the object thrown? c)
  5. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the
  6. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the
  7. Math

    In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of
  8. algebra

    An object is thrown straight up into the air at an initial vertical velocity of 32 feet per second from an initial height of 128 feet and is represented by the vertical motion model, h(t) = -16t^2 + 32t + 128. How much time does
  9. Math

    If an object is launched straight up into the air from a starting height of h_{0} feet, then the height of the object after t seconds is approximately h=-16t^2+v_{0}t+h_{0} feet, where v_{0} is the initial velocity of the object.
  10. Applied Calculus

    If an object is launched straight up into the air from a starting height of h_{0} feet, then the height of the object after t seconds is approximately h=-16t^2+v_{0}t+h_{0} feet, where v_{0} is the initial velocity of the object.

More Similar Questions