One 250mg tablet is made up of chemical A , B, ,C in a ratio 3:2:5. The Pharmacist Has 60mg of chemical B left. How much of Chemical A and C does she need if she uses 60mg of B?
3+2+5 = 10
250/10 = 25
75:50:125 is the required ratio for one tablet
we have 60mg of B, which is enough for 1.2 tablets
So, in theory, if she uses 60mg of B, she will end up using
90:60:150 mg of A:B:C
But who makes 1.2 pills?
To determine the amount of Chemical A and C required to balance 60mg of Chemical B, we need to determine the ratio between Chemical B and the other chemicals (A and C) in the tablet.
Given that the ratio of A, B, and C in one 250mg tablet is 3:2:5, we can express the ratio in terms of B. The total ratio is 10 (3+2+5 = 10), so we can calculate the ratio of B as follows:
Ratio of B = (amount of B in tablet) / (total ratio) = 2 / 10 = 1 / 5
So, for every 1 part of Chemical B, there are 3 parts of Chemical A and 5 parts of Chemical C in the tablet.
Since the pharmacist has 60mg of Chemical B left, we can determine the amounts of Chemical A and C needed by multiplying the ratio of B by 60mg:
Amount of A = (ratio of A to B) * (amount of B) = (3 / 5) * 60mg = 36mg
Amount of C = (ratio of C to B) * (amount of B) = (5 / 5) * 60mg = 60mg
Therefore, the pharmacist would need 36mg of Chemical A and 60mg of Chemical C to balance the 60mg of Chemical B.