Chemistry

In Europe, gasoline efficiency is measured in km/L . If your car's gas mileage is 28.0 mi/gal, how many liters of gasoline would you need to buy to complete a 142-km trip in Europe? Use the following conversions: 1km=(0.6214mi) and 1gal= (3.78L)

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  1. Convert 28.0 mi/gal to km/L. Use the conversion factors shown.
    28.0*(1 km/0.6214 mi)*(1 gal/3.78 L) = ?? km/L. Notice how the units you don't want (mi and gal) cancel and leaves the units you want to keep(km and L). You need to go through the calculation but the km/L is about 12.
    Then 142 km/12 km/L = ?? Again, you will need to use the correct value instead of 12. Post your work if you get stuck. Check my arithmetic. Check my units.

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  2. 11.9L

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  3. That's correct.

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  4. 15.9 L is the CORRECT ANSWER

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  5. While in Europe, if you drive 111km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 39.0mi/gal ? Assume that 1euro=1.26dollars.

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  6. 11.9

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  7. All of you are wrong. The answer is $82.20

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  8. I responded to the wrong thread lol. If the question was:
    "While in Europe, if you drive 101 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 28.0 mi/gal ? Assume that 1euro=1.26dollars."
    - then $82.20 would be correct

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