Time(seconds) 0 200 500 800 1200 1500
[A in Moles] .184 .129 .069 .031 .019 .016
What is the instantaneous rate of the reaction at t= 800 seconds?
Do you have any other information about the reaction?
Don't you need to plot concn vs time? The slope will be the instantaneous rate.
To find the instantaneous rate of the reaction at t=800 seconds, we need to calculate the rate of change of the concentration with respect to time at that specific moment.
The data provided gives the concentration of reactant A at different time intervals. To calculate the instantaneous rate at t=800 seconds, we can use the formula for the average rate of change:
Average rate of change = (Change in concentration) / (Change in time)
Since we are interested in the instantaneous rate at t=800 seconds, we need to consider a very small time interval around that point. In this case, we can choose the time interval between 500 and 800 seconds since it includes the desired point.
Change in concentration = [A] at t=800 seconds - [A] at t=500 seconds
= 0.031 - 0.069
= -0.038
Change in time = t at 800 seconds - t at 500 seconds
= 800 - 500
= 300 seconds
Now, we can calculate the average rate of change:
Average rate of change = -0.038 / 300
= -0.0001267 moles/second
Therefore, the instantaneous rate of the reaction at t=800 seconds is approximately -0.0001267 moles/second.