Two equals negatives charges (-1.75x10^(-19) Coulb) are separated by an insulator at a distance of 0.230 mm. Find the electrostatic force between these electrons?

That would amount to 1.1 electrons. You cannot have charge that is not an integral number of electron charges.

To calculate the electrostatic force between two charges, you can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

Coulomb's Law equation: F = k * (|q1| * |q2|) / r^2

Where:
F is the electrostatic force between the charges (in Newtons),
k is the electrostatic constant (k = 8.99 x 10^9 Nm^2/C^2),
|q1| and |q2| are the magnitudes of the charges, and
r is the distance between the charges (in meters).

In this case, both charges are equal and negative, so |q1| = |q2| = 1.75 x 10^(-19) C.
Also, the distance between the charges is given as 0.230 mm, which is 0.230 x 10^(-3) m.

Plugging in the values into Coulomb's Law equation:

F = (8.99 x 10^9 Nm^2/C^2) * (1.75 x 10^(-19) C * 1.75 x 10^(-19) C) / (0.230 x 10^(-3) m)^2

Calculating the force will give you the answer.