determine the molarity of each of the ions present in the following aqueous salt solutions
1.20M MgSO4
You have 1 Mg ion in a molecule of MgSO4; therefore, M Mg ion = M MgSO4.
You have 1 SO4 in in a molecule of MgSO4; therefore, M SO4 = M MgSO4.
To determine the molarity of each ion present in the solution of MgSO4, we need to understand the stoichiometry of the compound. MgSO4 consists of one magnesium ion (Mg2+) and one sulfate ion (SO42-).
Since MgSO4 is a fully dissociated ionic compound in water, it will release the ions completely. This means that in a 1.20M MgSO4 solution, the molarity of both Mg2+ and SO42- will be the same.
Therefore, the molarity of the Mg2+ ion is 1.20 M, and the molarity of the SO42- ion is also 1.20 M.