Determine the absolute pressure at the bottom of a lake that is 13.3 m deep. The acceleration of gravity is 9.8 m/s
2
and atmospheric
pressure is 1.01 × 10
5
Pa .
Answer in units of Pa
Well, the absolute pressure at the bottom of the lake can be calculated using the equation:
P = P₀ + ρgh
Where:
P is the absolute pressure at the bottom of the lake,
P₀ is the atmospheric pressure,
ρ is the density of the liquid (water),
g is the acceleration due to gravity, and
h is the depth of the lake.
So, let's plug in the values:
P = (1.01 × 10^5) + (ρ * 9.8 * 13.3)
Now, I'm not exactly sure what the density of the water is, but I can assure you that it definitely won't be denser than a group of clowns trying to squeeze into a tiny car. So, let's go with a safe estimate and assume the density of water to be 1000 kg/m³.
P = (1.01 × 10^5) + (1000 * 9.8 * 13.3)
Calculating this, we get:
P ≈ 1.01 × 10^5 + 129,340
P ≈ 230,340 Pa
So the absolute pressure at the bottom of the lake is approximately 230,340 Pa.
To determine the absolute pressure at the bottom of the lake, we need to consider the hydrostatic pressure due to the weight of the water above it.
The hydrostatic pressure can be calculated using the formula:
P = P0 + ρgh
Where:
P is the absolute pressure at the bottom of the lake,
P0 is the atmospheric pressure (1.01 × 105 Pa),
ρ is the density of the water (we'll assume ρ = 1000 kg/m3 for fresh water),
g is the acceleration due to gravity (9.8 m/s2),
and h is the depth of the lake (13.3 m).
Let's substitute the given values into the formula:
P = 1.01 × 105 Pa + (1000 kg/m3 * 9.8 m/s2 * 13.3 m)
P = 1.01 × 105 Pa + 129,340 Pa
P ≈ 229,340 Pa
Therefore, the absolute pressure at the bottom of the lake is approximately 229,340 Pa.
To determine the absolute pressure at the bottom of a lake, we need to consider the pressure due to the weight of the water column above it, as well as the atmospheric pressure.
The pressure due to the weight of the water column can be calculated using the formula:
P = ρgh
Where:
P is the pressure,
ρ is the density of the fluid (water),
g is the acceleration due to gravity, and
h is the depth of the fluid column.
First, we need to calculate the pressure due to the weight of the water column:
P_water = ρ × g × h
The density of water is approximately 1000 kg/m^3, and the acceleration due to gravity is 9.8 m/s^2. Plugging in the values, we get:
P_water = 1000 kg/m^3 × 9.8 m/s^2 × 13.3 m
Next, we need to consider the atmospheric pressure, which is given as 1.01 × 10^5 Pa.
Finally, we can calculate the absolute pressure at the bottom of the lake by adding the pressure due to the weight of the water column and the atmospheric pressure:
Absolute Pressure = P_water + Atmospheric Pressure
Calculate P_water and you'll get the answer in units of Pascal (Pa).
Pabsolute = Po + (density)*g*(depth)
Use 1000 kg/m^3 for the density of water
Po is atmospheric pressure
1.01*10^5 + 1.30*10^5 = ___ Pa