A researcher studying the nutritional value of a new candy places a 4.90 gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.75 degrees Celsius. If the heat capacity of the calorimeter is 29.50 kJ - K^-1, how many nutritional calories are there per gram of the candy? Answer in cal/g
i got 6.02 kJ k^-1 ... if that's correct how can i convert this answer to cal/g?
How did you arrive at 6.02 kJ/K? I can't get that value.
deees nuts
To convert the answer from kilojoules (kJ) to calories (cal) and from kilogram (kg) to gram (g), you can follow these steps:
1. Start with your answer in kilojoules per kilogram (kJ/kg).
Your answer is 6.02 kJ/kg.
2. Convert kilojoules to calories.
There are 1 kilocalorie (kcal) per 4.184 kilojoules (kJ).
So, divide your answer by 4.184.
6.02 kJ/kg ÷ 4.184 = 1.44 kcal/kg
3. Convert kilograms to grams.
There are 1000 grams (g) per kilogram (kg).
So, multiply your answer by 1000.
1.44 kcal/kg × 1000 = 1440 cal/kg
4. Finally, convert calories per kilogram to calories per gram.
Divide your answer by 1000.
1440 cal/kg ÷ 1000 = 1.44 cal/g
Therefore, the nutritional value of the candy is approximately 1.44 calories per gram (cal/g).