Find the dimensions of the rectangle.The perimeter is given.
Rectangle: P= 210 ft.
w;side of rec.
2w=15;bottom of rectangle
Help!
To find the dimensions of the rectangle when the perimeter is given, we can use the formula for the perimeter of a rectangle which is P = 2(l + w), where P is the perimeter, l is the length, and w is the width.
In this case, we are given that the perimeter of the rectangle is 210 ft. So we can set up the equation:
210 = 2(l + w)
Now we need to use the information provided to find the values of l and w.
First, we are given that the bottom side of the rectangle is 15 ft, which means the width of the rectangle is 15 ft (w = 15).
Substituting w = 15 into the equation, we have:
210 = 2(l + 15)
Next, we need to solve this equation for the length (l).
Dividing both sides of the equation by 2, we get:
105 = l + 15
To isolate l, we subtract 15 from both sides:
105 - 15 = l
Therefore, l = 90 ft.
So the dimensions of the rectangle are length = 90 ft and width = 15 ft.
From your data:
2W + 2L = P
15 + 2L = 210
Subtract 15 from both sides, then divide both sides by 2.