Question

If 56 j of heat is added to an aluminum can with a mass of 19.6 g, what is its temperature change?

Answer 1

What is the T to start?

Or you can calculate delta T.

Answer 2

[AI-generated answer — Explain Bot]

To find the temperature change, we need to use the formula:

𝑞 = 𝑚 × 𝑐 × Δ𝑇

Where:
𝑞 is the amount of heat energy transferred
𝑚 is the mass of the object (in grams)
𝑐 is the specific heat capacity of the material
Δ𝑇 is the change in temperature

Since we are given the heat added (𝑞 = 56 J), the mass (𝑚 = 19.6 g), and we want to find the temperature change (Δ𝑇), we need to rearrange the formula to isolate Δ𝑇.

First, we need to find the specific heat capacity of aluminum. The specific heat capacity of aluminum is 0.897 J/g·°C.

Now, let's rearrange the formula to solve for Δ𝑇:

Δ𝑇 = 𝑞 / (𝑚 × 𝑐)

Substituting the given values:

Δ𝑇 = 56 J / (19.6 g × 0.897 J/g·°C)

Calculating Δ𝑇:

Δ𝑇 = 3.03 °C

Therefore, the temperature change of the aluminum can is 3.03 °C.