write the expression using negative exponents. (4/3x)+(4/x^2)-(7x/5thsqrroot2x)
and
Write the fraction as a sum or two or more terms.
(6x^3-8x^2+4)/(x^(1/4)
I will start you out on the first:
4*(3x)-1+ 4(x-2+7x(2x)-7/2
THANK YOU!!!
To write the expression using negative exponents, you can follow these steps:
1. For (4/3x), the exponent of x is 1. To make it a negative exponent, we can rewrite it as 4/(3x)^1.
2. For (4/x^2), the exponent of x is 2. To make it a negative exponent, we can rewrite it as 4/(x^2)^1.
3. For (7x/5th√2x), the exponent of x is 1. To make it a negative exponent, we can rewrite it as 7x/(5th√2x)^1.
Therefore, the expression with negative exponents becomes: 4/(3x)^1 + 4/(x^2)^1 - 7x/(5th√2x)^1.
To write the fraction (6x^3-8x^2+4)/(x^(1/4)) as a sum of two or more terms, you need to break up the fraction using the rules of algebraic manipulation:
1. Separate all the terms in the numerator: 6x^3 - 8x^2 + 4.
2. Rewrite the denominator using the exponent rule for division: x^(1/4) = √x.
3. Distribute the denominator to each term in the numerator: (6x^3/√x) - (8x^2/√x) + (4/√x).
Therefore, the fraction (6x^3-8x^2+4)/(x^(1/4)) can be written as the sum of three terms: (6x^3/√x) - (8x^2/√x) + (4/√x).