A hydraulic jack is designed so that when the handle is pushed down 1 m, the piston raising the load moves up 0.015 m.
IMA= 66.67
AMA= 26.67
Efficiency= 40%
At this efficiency, what is the force required to lift a 5000 N weight?
To calculate the force required to lift a 5000 N weight using a hydraulic jack at a given efficiency, we can use the formula for mechanical advantage (MA) which is given by:
MA = IMA / AMA
Where:
IMA is the ideal mechanical advantage.
AMA is the actual mechanical advantage.
We are given that the IMA is equal to 66.67 and the AMA is equal to 26.67.
First, we need to use the formula for efficiency (Efficiency = MA / IMA) to find the efficiency of the hydraulic jack. Rearranging the formula, we have:
MA = Efficiency * IMA
Inserting the given values:
26.67 = 0.40 * 66.67
Next, we can solve for the force required to lift the weight by using the formula for force (Force = Load / MA):
Force = 5000 N / 26.67
Solving this equation, we get the force required to lift the weight using the given hydraulic jack efficiency.