If I have a unit vector of (2.06 j)m/s(I have no i vector because it's 0 on a horizontal impulsion, in accordance with my problem,how do I convert that into polar notation? Will I be doing rcos0, with r being 2.06? . But then again I have no angle, just the angle of before the ball bounces, which was of 70*. Can I simply go with arcTAN of 2,06, but that doesn't seem right to me.
Thank you
(0i+2.06j) is just (2.06,pi/2) in polar coordinates.
thank you
To convert a vector into polar notation, you need both the magnitude (r) and the angle (θ) of the vector. In your case, you have a unit vector with a y-component of 2.06 m/s.
Since the vector is a unit vector, its magnitude is always equal to 1. Therefore, the magnitude (r) of the vector is 1.
To find the angle (θ) of the vector, you mentioned that the angle before the ball bounces is 70°. However, it's important to note that the angle is measured with respect to the positive x-axis in standard practice.
Taking this into consideration, we can calculate the angle (θ) using the inverse tangent function as follows:
θ = arctan(y/x)
In this case, since the x-component is 0, we would have:
θ = arctan(2.06/0)
However, division by zero is not defined. Therefore, we cannot directly find the angle using this approach.
If you need to convert a vector into polar notation, it typically requires values for both the x and y components of the vector. In your case, since the x component is zero, it is not possible to determine the angle using standard methods.
However, if you have additional information or a different approach to determining the angle, please provide it, and I will be happy to help further.