A stone is catapulted at time t = 0, with an initial velocity of magnitude 20.2 m/s and at an angle of 39.1° above the horizontal. What are the magnitudes of the (a) horizontal and (b) vertical components of its displacement from the catapult site at t = 1.10 s? Repeat for the (c) horizontal and (d) vertical components at t = 1.73 s.
Call the horizontal displacement X and the vertical displacement Y.
X = 20.2 cos39.1 * t
Y = 20.2 sin39.1 * t - 4.9 t^2
Plug in the appropriate times (t) to get the answers they want.posted by drwls