in triangle abc angle a is (3x+40) angle b is (8x+35) and c is 10x what is the longest side of the triangle
3x+40 + 8x+35 + 10x = 180
21x = 105
x = 5
angles are
A = 55°
B = 75°
C = 50°
The longest side is opposite the angle 75°
21x = 105
x = 5
angles are
A = 55°
B = 75°
C = 50°
The longest side is opposite the angle 75°