An athlete swings a 3.46 kg ball horizontally

on the end of a rope. The ball moves in a
circle of radius 0.55 m at an angular speed of
0.35 rev/s.
What is the tangential speed of the ball?

0.35 rev/s means that w = 2.20 rad/s

is the so-called angular velocity

Multiply w by the radius for the tangential speed.

if the tangential speed of a ball is 1.2874 . what is the centripetal force ?

If the maximum tension the rope can withstand before breaking is 159.9 N, what is the
maximum tangential speed the ball can have?
Answer in units of m/s

To find the tangential speed of the ball, we need to use the formula:

Tangential Speed = angular speed x radius

Given:
Angular speed = 0.35 rev/s
Radius = 0.55 m

Let's calculate the tangential speed:

Tangential Speed = 0.35 rev/s x 0.55 m

Calculating:

Tangential Speed = 0.1925 m/s

Therefore, the tangential speed of the ball is 0.1925 m/s.

To calculate the tangential speed of the ball, we need to use the formula:

v = ωr

Where:
v is the tangential speed
ω (omega) is the angular speed in radians per second
r is the radius of the circular path

First, let's convert the given angular speed from revolutions per second to radians per second. Since there are 2π radians in one revolution, we can multiply the given angular speed by 2π:

ω = 0.35 rev/s * 2π rad/rev
ω ≈ 0.35 * 2π rad/s

Next, we can substitute the values into the formula to find the tangential speed:

v = ω * r
v ≈ (0.35 * 2π) rad/s * 0.55 m

Calculating this expression will give us the tangential speed of the ball.