A MASS OF A MINUBUS WITH THE DRIVER IS 1 500Kg .ASSUME THAT THE PASSENGERS HAV AN AVERAGE MASS OF 50Kg EACH .THE DRIVER IS MOVING AT A SPEED OF 30m.s WHE HE NOTICES THAT THE TRAFFIC LIGHTS AHEAD TURNED TO RED .HE APPLIES A FORCE OF 9 000N ON THE BREAK PEDAL .HOW LONG WILL IT TAKE HIM TO STOP AND HOW FAR HE BE FROM THE TRAFFIC LIGHTS IF HE WERE TO STOP IN TIME?
DON'T KNOW -- HOW MANY PASSENGERS ARE THERE? HOW FAR FROM THE STOP LIGHT DOES HE APPLY THE BRAKES?
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But you know
F=ma, which will give you the acceleration
v = at, which will give you the stopping time
s = 1/2 at^2, which will give you the stopping distance.
physics
To solve this problem, we need to use the equations of motion and Newton's second law of motion.
1. First, let's calculate the total mass of the minibus and passengers:
Mass of minibus = 1,500 kg
Mass of each passenger = 50 kg
Number of passengers = Let's assume there are 'x' passengers
Total mass = Mass of minibus + (Mass of each passenger * Number of passengers)
= 1,500 kg + (50 kg * x)
2. Now, let's apply Newton's second law of motion to find the net force acting on the minibus:
Net force = mass * acceleration
Since the driver is applying the brake, the acceleration is negative (opposite to the direction of motion).
Mass = Total mass calculated in step 1
Acceleration = -30 m/s^2 (deceleration)
Net force = (1,500 kg + 50 kg * x) * (-30 m/s^2)
3. Next, let's calculate the stopping distance (the distance traveled while stopping):
In order to calculate the stopping distance, we need the deceleration and initial velocity.
Deceleration (acceleration) = -30 m/s^2
Initial velocity = 30 m/s (given)
Stopping distance = (Initial velocity)^2 / (2 * |deceleration|)
4. Finally, let's calculate the time taken to stop:
We can use the equation of motion:
Final velocity^2 = Initial velocity^2 + 2 * acceleration * distance
Final velocity = 0 (since the minibus comes to rest)
Distance = stopping distance calculated in step 3
0 = (30 m/s)^2 + 2 * acceleration * distance
Solve for acceleration = -30 m/s^2
Solve for distance = stopping distance calculated in step 3
To get the exact values and solve the equations, we need the numerical values for the number of passengers and the stopping distance mentioned in the problem.