A student heats 9.85 g of lead to a temperature of 92.3 C. He places the hot lead into a container of water, initially at a temperature of 23.7 C; the final temperature of the water and lead is 24.5 C. What quantity of heat was lost by the lead?
q = heat lost by Pb.
q = mass Pb x specific heat Pb x (Tfinal-Tinitial).
Solve for q, the only unknown in the equation.