If you burn 38.9 g of hydrogen and produce 348 g of water, how much oxygen is reacted?
Just follow the steps in this example.
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To determine the amount of oxygen reacted, we can start by calculating the amount of hydrogen that reacted with oxygen using the molar ratio from the balanced chemical equation.
The balanced chemical equation for the reaction of hydrogen with oxygen to form water is: 2H₂ + O₂ → 2H₂O
The molar ratio between hydrogen and oxygen is 2:1, meaning that for every 2 moles of hydrogen reacted, 1 mole of oxygen is reacted.
To find the amount of oxygen reacted, we need to know the molar mass of hydrogen and oxygen.
The molar mass of hydrogen (H₂) is 2 g/mol, and we can calculate the number of moles of hydrogen reacted using the given mass of hydrogen (38.9 g) and its molar mass:
moles of hydrogen = mass of H₂ / molar mass of H₂
moles of hydrogen = 38.9 g / 2 g/mol
moles of hydrogen = 19.45 mol
Since the molar ratio between hydrogen and oxygen is 2:1, the number of moles of oxygen reacted is half the number of moles of hydrogen reacted:
moles of oxygen = 1/2 * moles of hydrogen
moles of oxygen = 1/2 * 19.45 mol
moles of oxygen = 9.725 mol
Finally, we can calculate the mass of oxygen reacted using the number of moles of oxygen and the molar mass of oxygen:
mass of oxygen = moles of oxygen * molar mass of O₂
mass of oxygen = 9.725 mol * 32 g/mol
mass of oxygen = 311.2 g
Therefore, approximately 311.2 grams of oxygen are reacted.
To determine the amount of oxygen reacted, we need to use the balanced chemical equation for the reaction between hydrogen and oxygen to form water:
2H₂ + O₂ → 2H₂O
From the equation, we can see that it takes two moles of hydrogen to react with one mole of oxygen to produce two moles of water.
To find the number of moles of water produced, we first need to convert the mass of water produced (348 g) into moles using the molar mass of water.
The molar mass of water (H₂O) is:
2(1.01 g/mol) + 16.00 g/mol = 18.02 g/mol
Number of moles of water produced = mass of water / molar mass of water
= 348 g / 18.02 g/mol ≈ 19.32 mol
Since the mole ratio between water and oxygen is 2:1, the number of moles of oxygen reacted would be half of the moles of water produced.
Number of moles of oxygen reacted = 1/2 * number of moles of water produced
= 1/2 * 19.32 mol ≈ 9.66 mol
Finally, to find the mass of oxygen reacted, we can multiply the number of moles of oxygen reacted by the molar mass of oxygen (O₂).
The molar mass of oxygen (O₂) is:
2(16.00 g/mol) = 32.00 g/mol
Mass of oxygen reacted = number of moles of oxygen reacted * molar mass of oxygen
= 9.66 mol * 32.00 g/mol ≈ 309.12 g
Therefore, approximately 309.12 grams of oxygen reacted.