If you burn 38.9 g of hydrogen and produce 348 g of water, how much oxygen is reacted?
To find out how much oxygen is reacted, we need to use the stoichiometry of the chemical equation for the combustion of hydrogen.
The balanced equation for the combustion of hydrogen is:
2 H₂ + O₂ → 2 H₂O
From the equation, we can see that the ratio of H₂ to O₂ is 2:1.
Given that 38.9 g of hydrogen is reacted and 348 g of water is produced, we can determine the amount of oxygen reacted as follows:
1. Convert the mass of hydrogen to moles:
Molar mass of hydrogen (H₂) = 2.02 g/mol
Number of moles of hydrogen = mass of hydrogen / molar mass of hydrogen
Number of moles of hydrogen = 38.9 g / 2.02 g/mol
2. Since the ratio of H₂ to O₂ is 2:1, the number of moles of oxygen reacted will be half the number of moles of hydrogen used.
Number of moles of oxygen reacted = (1/2) * number of moles of hydrogen
3. Convert the number of moles of oxygen reacted to grams:
Molar mass of oxygen (O₂) = 32.00 g/mol
Mass of oxygen reacted = number of moles of oxygen reacted * molar mass of oxygen
Mass of oxygen reacted = (1/2) * number of moles of hydrogen * 32.00 g/mol
Now we can calculate the amount of oxygen reacted:
Mass of oxygen reacted = (1/2) * (38.9 g / 2.02 g/mol) * 32.00 g/mol
Mass of oxygen reacted ≈ 320 g
Therefore, approximately 320 grams of oxygen is reacted.
To determine the amount of oxygen reacted in the given reaction, we need to use stoichiometry, which is the balanced equation for the reaction.
The balanced chemical equation for the combustion of hydrogen can be written as:
2H2 + O2 → 2H2O
From the equation, it can be seen that for every 2 moles of hydrogen gas (H2) reacted, 1 mole of oxygen gas (O2) is required.
To find the mole ratio between hydrogen and oxygen, let's convert the given mass of hydrogen to moles:
1 mole of H2 has a molar mass of 2.02 g.
Moles of hydrogen gas = mass of hydrogen / molar mass of hydrogen
Moles of hydrogen gas = 38.9 g / 2.02 g/mol
Moles of hydrogen gas = 19.30 mol
From the stoichiometry of the balanced equation, we know that 2 moles of hydrogen gas reacts with 1 mole of oxygen gas. Therefore, the moles of oxygen gas reacted can be calculated as:
Moles of oxygen gas = (Moles of hydrogen gas / 2)
Moles of oxygen gas = 19.30 mol / 2
Moles of oxygen gas = 9.65 mol
Now, to convert the moles of oxygen gas to grams, we use the molar mass of oxygen, which is 32.00 g/mol:
Mass of oxygen gas = moles of oxygen gas * molar mass of oxygen
Mass of oxygen gas = 9.65 mol * 32.00 g/mol
Mass of oxygen gas = 308.8 g
Therefore, approximately 308.8 grams of oxygen gas is reacted in the given combustion reaction.