how much calcium is there in 2.30 L of 0.0450 M calcium hydroxide solution ? pdf

grams of Ca= volume*molarity*atomicmassCa

because there is one Ca per atom.

oops one Ca per molecule

To determine the amount of calcium in a solution of calcium hydroxide, you will need to use the concentration of the solution and convert it into an amount of calcium. Here's how you can calculate it:

Step 1: Determine the molar mass of calcium hydroxide (Ca(OH)2).
The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of hydroxide (OH) is 17.01 g/mol (16.00 g/mol for oxygen + 1.01 g/mol for hydrogen). Multiply the molar mass of calcium by 1 (since there is only 1 calcium atom in the formula), and the molar mass of hydroxide by 2 (since there are 2 hydroxide ions in the formula). Then add the results together:

Molar mass of Ca(OH)2 = (40.08 g/mol × 1) + (17.01 g/mol × 2)
= 40.08 g/mol + 34.02 g/mol
= 74.10 g/mol

Step 2: Calculate the number of moles of calcium hydroxide.
To find the number of moles, you need to multiply the volume of the solution (in liters) by the concentration (in moles per liter). In this case, the volume is 2.30 L, and the concentration is 0.0450 M:

Number of moles = volume × concentration
= 2.30 L × 0.0450 M
= 0.1035 moles

Step 3: Calculate the amount of calcium.
Since calcium hydroxide dissociates into one calcium ion (Ca2+) for every formula unit, the number of moles of calcium will be the same as the number of moles of calcium hydroxide:

Amount of calcium = number of moles of calcium hydroxide
= 0.1035 moles

Step 4: Convert the amount of calcium to grams.
To convert moles to grams, you need to multiply the number of moles by the molar mass of calcium:

Amount of calcium in grams = moles of calcium × molar mass of calcium
= 0.1035 moles × 40.08 g/mol
= 4.15 grams

Therefore, there is approximately 4.15 grams of calcium in 2.30 L of 0.0450 M calcium hydroxide solution.