physics

A block with mass m =7.3 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.21 m. While at this equilibrium position, the mass is then given an initial push downward at v = 4.5 m/s. The block oscillates on the spring without friction.
At t = 0.35 s what is the magnitude of the net force on the block?

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asked by Chad
  1. Do your own work and stop looking on the Internet for answers.

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    posted by Chuck
  2. gtfo !@#$%^&^

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    2. 👎 6
    posted by Bob
  3. GET A LIFE CHUCK

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    posted by Neam
  4. Chuck, there's nothing wrong with asking for help on the Internet especially if someone lost. They, shouldn't expect someone to solve the problem for them. nor should the "tutor" give them the answer but explain the process and thinking why we use what eq. but yes just giving them the answer won't help them learn "how" "when" or "Why". but asking is better than staring at a wall of text and numbers they don't understand or trying guess and learning it wrong.

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    posted by adam
  5. In order to solve this, you first have to find the displacement at time 0.35, so using the equation x(t) = Asin(wt-shift), and then by using F=-kx you are able to solve for the net force on the block at that time

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    posted by Cora

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