# physics

what is the maximum speed with which a car can round a turn of radius of 80.0m on a flat road if the coefficient of friction between tires and the road is .700?

1. It matters if the road is banked. If unbanked, then force friction=centripetalForce

mg*mu=1/2 m v^2 / r
solve for v.

posted by bobpursley
2. I don't have a mass.

posted by Shea
3. bobpursley's comment is on the right track, but the equation IS wrong. mg(a.k.a. normal force) x Coefficient of friction = (m x v^2)/r then the normal force breaks down into: m x a(a = 9.8 at sea level) the equation will then look as so: 9.8m x mu = (mv^2)/r the m's will cancel out getting rid of mass. solve from there

posted by Kole
4. Kole is right but how would you find velocity

posted by Phil
5. You solve for velocity

posted by A

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