Find the slope.

(3,1/3) and (3+h, 1/(3+h))
I think I get -1/ 3(3+h)
???

Correct!

If you want the details:
Slope = (y2-y1)/(x2-x1)
=(1/(3+h)-1/3) / (3+h-3)
=([3-(3+h)]/[3(3+h)]) / (h)
=(-h/[3(3+h)])/h
=-1/[3(3+h)]