How many gallons of water can be contained in a cylindrical tank that is 6ft in diameter and 15ft deep?
To determine the number of gallons of water a cylindrical tank can hold, you need to calculate the volume of the tank and convert it to gallons.
1. Calculate the volume of the cylinder using the formula V = πr^2h, where V is the volume, r is the radius, and h is the height or depth of the cylinder.
Given that the diameter of the tank is 6ft, the radius (r) is half of the diameter, which is 6ft / 2 = 3ft.
The height or depth (h) of the tank is given as 15ft.
2. Substitute the values into the formula V = πr^2h:
V = π(3ft)^2 * 15ft
3. Calculate the volume:
V ≈ 3.14 * (3ft)^2 * 15ft
V ≈ 3.14 * 9ft^2 * 15ft
V ≈ 3.14 * 135ft^3
V ≈ 423.9ft^3
4. Convert the volume from cubic feet to gallons.
Since there are approximately 7.48 gallons in 1 cubic foot, we can multiply the volume by 7.48 to convert it to gallons.
423.9ft^3 * 7.48 gallons/ft^3 ≈ 3167.2 gallons
Therefore, the cylindrical tank can hold approximately 3167.2 gallons of water.
To find the number of gallons of water that can be contained in a cylindrical tank, we need to calculate the volume of the tank in cubic feet and then convert it to gallons.
First, let's find the volume of the tank. The formula for the volume of a cylinder is given by V = πr^2h, where V is the volume, π is a mathematical constant approximately equal to 3.14, r is the radius of the cylinder, and h is the height of the cylinder.
Given that the diameter of the tank is 6ft, we can find the radius by dividing it by 2: 6ft / 2 = 3ft.
The height of the tank is given as 15ft.
Now we have all the values we need. Let's calculate the volume:
V = πr^2h
V = 3.14 * (3ft)^2 * 15ft
V = 3.14 * 9ft^2 * 15ft
V = 423.9 cubic feet (approximately)
Next, we need to convert cubic feet to gallons.
One cubic foot is equal to approximately 7.48 gallons. To convert cubic feet to gallons, we multiply the volume in cubic feet by 7.48.
Number of gallons = 423.9 cubic feet * 7.48 gallons/cubic foot
Number of gallons ≈ 3,169.37 gallons
Therefore, the cylindrical tank with a diameter of 6ft and a depth of 15ft can hold approximately 3,169.37 gallons of water.
volume of tank = π(3^2)(15) = 135π
You will have to look up how many gallons of water in 1 cubic foot, I am a metric kind of guy.
Are we talking US gallons or Imperial gallons ?